In Exercises 13–14, graph each polar equation.r = 1 + sin θ

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Sketch the given polar equation and the polar coordinate system where we have R as equals to five plus cosine of theta. We're also given a coordinate plane to graph our equation. Now it's graph this, let's find some points to plug in for our graph. In particular, we need data values which are angles. We make an input output table with theta as our input radius R as our output. No, since we have a polar graph, our possible range of angles will be then from 0 to 2, the let's say we choose data equal zero, fair equals pi divided by two third equals pi equals three pi divided by two and finally two pi now we can plug these values in, we have R equals five plus cosine of the which will say zero first. Now we know cosine of zero from our unit circle is one five plus one, gives us six. Our next value will be pi divided by two. So you get five plus cosine five divided by two. Now, and pi divided by two is zero. So we just skip five as a result. Now we can plug in the rest of our values 45 and six. Let's go ahead and plot these points down. So for plotting polar coordinates, our angle will be our direction and we will move a certain amount of units in that direction for our radius. In other words, our data is zero first, which means we will move six units in that direction, which should give us a point on our axis here at six. Our next one is pi divided by 25. So we'll go to pi divided by two and go up by five and we'll do the same for the rest, go to left four and we go down five. Now I notice this is a circle so we can just make a curve connecting all points like so and now we have our graph to the equation. OK? I hope to help you solve the problem. Thank you for watching. Goodbye.

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In Exercises 13–14, graph each polar equation.r = 1 + sin θ

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