For each of the following compounds, indicate whether or not it can exist as cis–trans stereoisomers. If it can exist as the two isomers, draw both as a condensed structure.
(c)

Question

For each of the following compounds, indicate whether or not it can exist as cis–trans stereoisomers. If it can exist as the two isomers, draw both as a condensed structure.

(c)

Accepted Answer

Welcome back, everyone determine if the compound shown below can exhibit Crans stereoisomerism if it can draw both stereo isomers. First of all, we're given an LK and we want to draw the double bond, let's introduce the two carbon atoms and draw the double bond between them. And now we simply want to add the subscriptions for each double bonded carbon. Now the first one has hydrogen and then the muscle group, so we can arrange them as follows. First of all, we're adding hygen followed by the male group C string. For the next double bonded carbon, we can see that it has hydrogen followed by a propel group. So first of all, let's add hydrogen and then the other substituent would be the propel group C two ch two ch three. The very first question is, can this structure exhibit cran stereoisomerism? And the main condition is to make sure that every double bonded carbon has two different substituents. Now the first one has hygen and methyl, those are different and the second one has hydrogen and propi those are different. So we can say that yes, it can exhibit this trans stereo isomerism. Now, we have drawn the cis stereo isomer because the LQ groups or the highest priority groups are on the same side of the double bond, they are both below the double bond. And as we already understand the second structure, which will be the trans stereo isomer must have the highest priority groups or basically the LK subs stations on opposite sides of the double bond. Now, how do we draw the trend structure? Well, essentially we want to swap the positions of hydrogen in the propel group. This is just an example, we can do it multiple ways, but we want to make sure that the end result is that the two lky groups are on opposite sides of the double bond. This is what we have achieved, right? Because now the muscle substituent and the prop substituent, they are on opposite sides of the double bond. And that will be the trans structure. And this allows us to finish the problem. We will simply label our final answers. And thank you for watching.

For each of the following compounds, indicate whether or not it can exist as cis–trans stereoisomers. If it can exist as the two isomers, draw both as a condensed structure.
(c)

Verified video answer for a similar problem:

Key Concepts

Cis-Trans Stereoisomerism

Criteria for Cis-Trans Isomerism

Condensed Structural Formula

For each of the following compounds, indicate whether or not it can exist as cis–trans stereoisomers. If it can exist as the two isomers, draw both as a condensed structure.(c)