A pea plant that has the genotype RrGgwwdd is crossed to a plant that has the rrGgWwDd genotype. The R gene controls round versus wrinkled seed, the G gene controls yellow versus green seed, the W gene controls purple versus white flower, and the D gene controls tall versus short plants. Determine the following;
What proportion of the progeny are expected to have the genotype RrGGwwDd?
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
2. Mendel's Laws of Inheritance
Probability and Genetics
Struggling with Genetics?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
In a family of five children what is the probability that… Two are males and three are females
A
0.31, 31%
B
0.5, 50%
C
0.25, 25%
D
0.10, 10%

1
Understand that the problem involves a binomial probability distribution, where each child can be either male or female with equal probability of 0.5.
Identify that you need to find the probability of exactly two males (and thus three females) in five children.
Use the binomial probability formula: P(X = k) = C(n, k) * (p^k) * ((1-p)^(n-k)), where n is the total number of trials (children), k is the number of successful trials (males), and p is the probability of success on a single trial (0.5 for male).
Calculate the binomial coefficient C(n, k) = n! / (k!(n-k)!), which represents the number of ways to choose k successes (males) from n trials (children). For this problem, calculate C(5, 2).
Substitute the values into the binomial probability formula to find the probability of exactly two males in five children: P(X = 2) = C(5, 2) * (0.5^2) * (0.5^3).
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