Situs inversus is a congenital condition in which the major visceral organs are reversed from their normal positions. Investigations into the genetics of this abnormality revealed that individuals with at least one dominant allele (SI) of an autosomal gene are normal but, surprisingly, of individuals that are homozygous for a recessive allele (si), 1/2 are situs inversus and 1/2 are normal.
What genotypes and phenotypes are expected in progeny from a cross of two si si individuals?
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
2. Mendel's Laws of Inheritance
Probability and Genetics
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Use the product law to calculate the probability that mating two organisms with the genotype of AaBbCcDd will produce offspring with the genotype of AA bb Cc Dd?
A
1/4
B
1/16
C
1/64
D
1/128

1
Identify the genotype of the parents: Both parents have the genotype AaBbCcDd.
Determine the probability of each gene pair resulting in the desired genotype in the offspring. For each gene pair, calculate the probability separately.
For the AA genotype: The probability of getting AA from Aa x Aa is 1/4.
For the bb genotype: The probability of getting bb from Bb x Bb is 1/4.
For the Cc and Dd genotypes: The probability of getting Cc from Cc x Cc is 1/2, and the probability of getting Dd from Dd x Dd is 1/2. Multiply these probabilities together using the product law to find the overall probability of the offspring having the genotype AA bb Cc Dd.
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