Floral traits in plants often play key roles in diversification, in that slight modifications of those traits, if genetically determined, may quickly lead to reproductive restrictions and evolution. Insight into genetic involvement in flower formation is often acquired through selection experiments that expose realized heritability. Lendvai and Levin (2003) conducted a series of artificial selection experiments on flower size (diameter) in Phlox drummondii. Data from their selection experiments are presented in the following table in modified form and content.
In terms of evolutionary potential, is a population with high heritability likely to be favored compared to one with a low realized heritability?
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
20. Quantitative Genetics
Heritability
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The narrow-sense heritability of the number of seeds per flower is 0.9. The mean of the population is 6.0 seeds per flower. A flower breeder crosses one flower with 7 seeds to another plant with 9 seeds. What is the expected number of seeds per flower in the offspring of this cross?
A
5
B
6
C
7
D
8

1
Understand that narrow-sense heritability (h^2) is the proportion of phenotypic variance that is attributable to additive genetic variance. In this problem, h^2 is given as 0.9.
Recognize that the breeder's equation can be used here: R = h^2 * S, where R is the response to selection, and S is the selection differential.
Calculate the selection differential (S), which is the difference between the mean phenotype of the selected parents and the mean phenotype of the population. Here, the selected parents have an average of (7 + 9) / 2 = 8 seeds per flower, and the population mean is 6 seeds per flower. Thus, S = 8 - 6.
Apply the breeder's equation: R = h^2 * S. Substitute the given values: R = 0.9 * (8 - 6).
Determine the expected mean of the offspring by adding the response to selection (R) to the original population mean. This will give you the expected number of seeds per flower in the offspring.
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