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Multiple Choice
CH3OH can be synthesized by the reaction CO(g) + 2H2(g) → CH3OH(g). How many liters of CO gas are required to produce 44.8 liters of CH3OH gas at STP?
A
11.2 liters
B
33.6 liters
C
44.8 liters
D
22.4 liters
Verified step by step guidance
1
Identify the balanced chemical equation for the reaction: CO(g) + 2H2(g) → CH3OH(g). This equation shows that 1 mole of CO reacts with 2 moles of H2 to produce 1 mole of CH3OH.
Recall that at Standard Temperature and Pressure (STP), 1 mole of any ideal gas occupies 22.4 liters.
Determine the relationship between the volumes of gases involved in the reaction. Since the reaction is 1:1 for CO to CH3OH, 1 mole of CO will produce 1 mole of CH3OH.
Calculate the volume of CO needed to produce 44.8 liters of CH3OH. Since 44.8 liters of CH3OH corresponds to 2 moles (because 44.8 L / 22.4 L/mol = 2 mol), you will need 2 moles of CO.
Convert the moles of CO to volume at STP. Since 1 mole of CO occupies 22.4 liters, 2 moles of CO will occupy 44.8 liters. Therefore, 44.8 liters of CO are required to produce 44.8 liters of CH3OH at STP.