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Multiple Choice
Consider the following balanced reaction. What mass (in g) of CO2 can be formed from 288 mg of O2? Assume that there is excess C3H7SH present.C3H7SH(l) + 6 O2(g) β 3 CO2(g) + SO2(g) + 4 H2O(g)
A
0.297 g
B
0.396 g
C
0.099 g
D
0.198 g
Verified step by step guidance
1
First, convert the mass of O2 from milligrams to grams. Since 1 mg = 0.001 g, multiply 288 mg by 0.001 to get the mass in grams.
Next, calculate the number of moles of O2 using its molar mass. The molar mass of O2 is approximately 32.00 g/mol. Use the formula: \( \text{moles of O}_2 = \frac{\text{mass of O}_2}{\text{molar mass of O}_2} \).
Using the stoichiometry of the balanced equation, determine the moles of CO2 produced. According to the equation, 6 moles of O2 produce 3 moles of CO2. Therefore, use the ratio \( \frac{3 \text{ moles CO}_2}{6 \text{ moles O}_2} \) to find the moles of CO2.
Calculate the mass of CO2 formed using its molar mass. The molar mass of CO2 is approximately 44.01 g/mol. Use the formula: \( \text{mass of CO}_2 = \text{moles of CO}_2 \times \text{molar mass of CO}_2 \).
Finally, ensure that the mass of CO2 is expressed in grams and verify that it matches one of the given options.