Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Stoichiometry

General Chemistry

3. Chemical Reactions

Stoichiometry

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Multiple Choice

Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is excess NO2 present. The molar masses are as follows: H2O = 18.02 g/mol, HNO3 = 63.02 g/mol.3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

20.00 g

15.00 g

10.86 g

5.43 g

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Verified step by step guidance

Identify the balanced chemical equation: 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g). This tells us the stoichiometric relationship between the reactants and products.

Determine the molar mass of the substances involved. For H2O, it is 18.02 g/mol, and for HNO3, it is 63.02 g/mol.

Calculate the moles of HNO3 needed using its molar mass. Use the formula: moles of HNO3 = mass of HNO3 / molar mass of HNO3. Substitute the given mass of HNO3 (75.9 g) and its molar mass (63.02 g/mol) into the formula.

Use the stoichiometry of the balanced equation to find the moles of H2O required. According to the equation, 2 moles of HNO3 are produced per 1 mole of H2O. Therefore, calculate the moles of H2O using the ratio: moles of H2O = (moles of HNO3) * (1 mole H2O / 2 moles HNO3).

Convert the moles of H2O to grams using its molar mass. Use the formula: mass of H2O = moles of H2O * molar mass of H2O. Substitute the calculated moles of H2O and the molar mass of H2O (18.02 g/mol) into the formula to find the mass of water required.