Multiple Choice
You need to prepare 2.00 L of 0.100 M Na2CO3 solution. The best procedure is to weigh out:
6. Chemical Quantities & Aqueous Reactions
Molarity
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What is the molarity of a solution prepared by dissolving 5.0 grams of NaCl (molar mass = 58.44 g/mol) in enough water to make 250 mL of solution?
A
0.214 M
B
0.342 M
C
0.500 M
D
0.684 M
Verified step by step guidance1
Calculate the number of moles of NaCl by using the formula: \( \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \). Substitute the given values: mass = 5.0 g and molar mass = 58.44 g/mol.
Convert the volume of the solution from milliliters to liters, since molarity is expressed in moles per liter. Use the conversion: \( 1 \text{ L} = 1000 \text{ mL} \). Therefore, \( 250 \text{ mL} = 0.250 \text{ L} \).
Use the formula for molarity: \( M = \frac{\text{moles of solute}}{\text{liters of solution}} \). Substitute the moles of NaCl calculated in step 1 and the volume in liters from step 2.
Perform the division to find the molarity of the solution. This will give you the concentration of the NaCl solution in moles per liter (M).
Compare the calculated molarity with the given options to determine which one matches your result.
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