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Multiple Choice
Determine the molarity of a solution formed by dissolving 97.7 g of LiBr in enough water to yield 750.0 mL of solution.
A
1.54 M
B
0.65 M
C
2.00 M
D
0.85 M
Verified step by step guidance
1
Calculate the molar mass of LiBr. Lithium (Li) has an atomic mass of approximately 6.94 g/mol, and bromine (Br) has an atomic mass of approximately 79.90 g/mol. Add these values to find the molar mass of LiBr.
Convert the mass of LiBr from grams to moles using the molar mass calculated in the previous step. Use the formula: \( \text{moles of LiBr} = \frac{\text{mass of LiBr (g)}}{\text{molar mass of LiBr (g/mol)}} \).
Convert the volume of the solution from milliliters to liters, since molarity is expressed in moles per liter. Use the conversion: \( 1 \text{ L} = 1000 \text{ mL} \).
Calculate the molarity of the solution using the formula: \( \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
Compare the calculated molarity with the given options to determine the correct answer.