Multiple Choice
Calculate the number of grams of KOH in 250.0 mL of a 0.189 M solution.
6. Chemical Quantities & Aqueous Reactions
Molarity
Struggling with General Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Determine the molarity of a solution prepared by dissolving 11.5 g of NaOH to form a 250.0 mL solution. (Molar mass of NaOH = 40.00 g/mol)
A
0.230 M
B
0.920 M
C
0.460 M
D
0.115 M
Verified step by step guidance1
First, calculate the number of moles of NaOH using the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \). Here, the mass of NaOH is 11.5 g and the molar mass is 40.00 g/mol.
Substitute the given values into the formula: \( \text{moles of NaOH} = \frac{11.5 \text{ g}}{40.00 \text{ g/mol}} \).
Next, convert the volume of the solution from milliliters to liters, since molarity is expressed in moles per liter. The volume of the solution is 250.0 mL, which is equivalent to 0.250 L.
Now, use the formula for molarity: \( \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
Substitute the calculated moles of NaOH and the volume in liters into the molarity formula to find the molarity of the solution.
Related Videos
Related Practice
