Multiple Choice
Calculate the mass of malonic acid, CH₂(COOH)₂, required to make 25 mL of a solution that is 0.15 M in malonic acid.
6. Chemical Quantities & Aqueous Reactions
Molarity
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What is the molarity of a solution made by dissolving 10.0 g of sodium chloride (58.44 g/mol) in 750.0 mL of solution?
A
0.175 M
B
0.133 M
C
0.228 M
D
0.267 M
Verified step by step guidance1
Calculate the number of moles of sodium chloride (NaCl) using the formula: \( \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \). Here, the mass is 10.0 g and the molar mass of NaCl is 58.44 g/mol.
Substitute the given values into the formula: \( \text{moles of NaCl} = \frac{10.0 \text{ g}}{58.44 \text{ g/mol}} \).
Calculate the volume of the solution in liters. Since the volume is given in milliliters (750.0 mL), convert it to liters by dividing by 1000: \( \text{volume (L)} = \frac{750.0 \text{ mL}}{1000} \).
Use the formula for molarity: \( M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
Substitute the calculated moles of NaCl and the volume in liters into the molarity formula to find the molarity of the solution.
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