Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Complete and balance given reaction. BaH2(s) + H2O(l) →
A
BaH2(s) + 2 H2O(l) → 2 O2(g) + BaH4(aq)
B
BaH2(s) + 2 H2O(l) → 2 H2O2(l) + Ba(s)
C
2 BaH2(s) + 2 H2O(l) → 2 Ba(OH)2(aq)
D
BaH2(s) + 2 H2O(l) → 2 H2(g) + Ba(OH)2(aq)
Verified step by step guidance
1
Identify the reactants and products in the given chemical equation. The reactants are BaH2(s) and H2O(l), and the products are H2(g) and Ba(OH)2(aq).
Write the unbalanced chemical equation: BaH2(s) + H2O(l) → H2(g) + Ba(OH)2(aq).
Balance the equation by ensuring the number of atoms of each element is the same on both sides. Start by balancing the barium (Ba) atoms. There is 1 Ba atom on both sides, so they are balanced.
Next, balance the hydrogen (H) atoms. There are 2 H atoms in BaH2 and 2 H atoms in each H2O molecule on the reactant side, totaling 4 H atoms. On the product side, there are 2 H atoms in each H2 molecule and 2 H atoms in Ba(OH)2, totaling 4 H atoms. To balance, ensure there are 2 H2 molecules on the product side.
Finally, balance the oxygen (O) atoms. There are 2 O atoms in 2 H2O molecules on the reactant side and 2 O atoms in Ba(OH)2 on the product side. The equation is now balanced: BaH2(s) + 2 H2O(l) → 2 H2(g) + Ba(OH)2(aq).