Multiple Choice
How many grams of CH₃OH must be added to water to prepare 150 mL of a solution that is 2.00 M CH₃OH?
6. Chemical Quantities & Aqueous Reactions
Molarity
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How many grams of sucrose (C₁₂H₂₂O₁₁) are in 1.55 L of 0.758 M sucrose solution?
A
400.1 grams
B
250.8 grams
C
320.5 grams
D
150.2 grams
Verified step by step guidance1
Identify the given information: the volume of the solution is 1.55 L and the molarity (M) of the sucrose solution is 0.758 M.
Recall that molarity (M) is defined as moles of solute per liter of solution. Use the formula: \( \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} \).
Calculate the moles of sucrose using the formula: \( \text{moles of sucrose} = \text{Molarity} \times \text{Volume in liters} \). Substitute the given values: \( 0.758 \text{ M} \times 1.55 \text{ L} \).
Determine the molar mass of sucrose (C₁₂H₂₂O₁₁) by adding the atomic masses of all the atoms in the formula: \( 12 \times 12.01 \text{ g/mol} + 22 \times 1.01 \text{ g/mol} + 11 \times 16.00 \text{ g/mol} \).
Calculate the mass of sucrose in grams using the formula: \( \text{mass} = \text{moles of sucrose} \times \text{molar mass of sucrose} \).
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