Multiple Choice
How many grams of calcium nitrate (Ca(NO3)2) are required to prepare 500.0 mL of a 0.500 M calcium nitrate solution?
6. Chemical Quantities & Aqueous Reactions
Molarity
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
How many milliliters of 18.0 M H₂SO₄ are required to prepare 1.00 L of a 0.900 M solution?
A
25.0 mL
B
50.0 mL
C
10.0 mL
D
5.00 mL
Verified step by step guidance1
Start by using the dilution formula, which is: \( C_1V_1 = C_2V_2 \), where \( C_1 \) and \( V_1 \) are the concentration and volume of the stock solution, and \( C_2 \) and \( V_2 \) are the concentration and volume of the diluted solution.
Identify the known values: \( C_1 = 18.0 \) M, \( C_2 = 0.900 \) M, and \( V_2 = 1.00 \) L. You need to find \( V_1 \), the volume of the stock solution.
Rearrange the dilution formula to solve for \( V_1 \): \( V_1 = \frac{C_2V_2}{C_1} \).
Substitute the known values into the rearranged formula: \( V_1 = \frac{0.900 \times 1.00}{18.0} \).
Calculate \( V_1 \) to find the volume in liters, then convert it to milliliters by multiplying by 1000, since 1 L = 1000 mL.
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