Multiple Choice
Determine the molarity of acetic acid if 13.45 mL of acetic acid requires 22.73 mL of 0.112 M NaOH for complete neutralization. Assume the reaction is 1:1.
6. Chemical Quantities & Aqueous Reactions
Molarity
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How many grams of NaOH are required to make 0.350 L of a 0.500 M NaOH solution?
A
7.00 grams
B
3.50 grams
C
5.25 grams
D
1.75 grams
Verified step by step guidance1
Identify the formula for molarity: \( M = \frac{\text{moles of solute}}{\text{liters of solution}} \).
Rearrange the formula to solve for moles of solute: \( \text{moles of solute} = M \times \text{liters of solution} \).
Substitute the given values into the equation: \( \text{moles of NaOH} = 0.500 \, M \times 0.350 \, L \).
Calculate the moles of NaOH using the substituted values.
Convert moles of NaOH to grams using the molar mass of NaOH (approximately 40.00 g/mol): \( \text{grams of NaOH} = \text{moles of NaOH} \times 40.00 \, \text{g/mol} \).
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