Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Stoichiometry

General Chemistry

3. Chemical Reactions

Stoichiometry

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Multiple Choice

How many moles of carbon dioxide are produced in the combustion reaction of 65.14 g of C5H10(g)?2C5H10(g) + 15O2(g) → 10CO2(g) + 10H2O(l)

1.86 moles

3.72 moles

4.65 moles

0.93 moles

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Verified step by step guidance

First, identify the balanced chemical equation for the combustion of C5H10: 2C5H10(g) + 15O2(g) → 10CO2(g) + 10H2O(l). This equation shows the stoichiometric relationship between reactants and products.

Calculate the molar mass of C5H10. The molar mass is determined by adding the atomic masses of all atoms in the molecule: C (12.01 g/mol) and H (1.01 g/mol). Therefore, the molar mass of C5H10 is (5 * 12.01) + (10 * 1.01) g/mol.

Convert the given mass of C5H10 (65.14 g) to moles using the molar mass calculated in the previous step. Use the formula: \( \text{moles of C5H10} = \frac{\text{mass of C5H10}}{\text{molar mass of C5H10}} \).

Use the stoichiometry of the balanced equation to find the moles of CO2 produced. According to the equation, 2 moles of C5H10 produce 10 moles of CO2. Set up a proportion: \( \frac{\text{moles of CO2}}{\text{moles of C5H10}} = \frac{10}{2} \).

Finally, calculate the moles of CO2 produced by multiplying the moles of C5H10 by the stoichiometric ratio obtained in the previous step. This will give you the moles of CO2 produced in the reaction.