Using the equations below, determine the molar enthalpy change (ΔH°) for the combustion of octane (C₈H₁₈) in kJ/mol. 1. 2 C₈H₁₈ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g) ΔH° = -6271 kJ/mol2. 2 H₂ (g) + O₂ (g) → 2 H₂O (g) ΔH° = -483.6 kJ/mol3. C (s) + O₂ (g) → CO₂ (g) ΔH° = -393.5 kJ/mol