Multiple Choice
A solution of LiCl in water has a mole fraction of LiCl, X(LiCl) = 0.0800. What is the molality of the solution?
14. Solutions
Molality
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How many moles of KF are contained in 347 g of water in a 0.175 m KF solution?
A
0.347 moles
B
0.175 moles
C
0.0607 moles
D
0.500 moles
Verified step by step guidance1
Understand the concept of molality, which is defined as the number of moles of solute per kilogram of solvent. In this problem, KF is the solute and water is the solvent.
Convert the mass of water from grams to kilograms. Since 1 kg = 1000 g, divide 347 g by 1000 to get the mass in kilograms.
Use the formula for molality: \( m = \frac{\text{moles of solute}}{\text{kilograms of solvent}} \). Rearrange the formula to solve for moles of solute: \( \text{moles of solute} = m \times \text{kilograms of solvent} \).
Substitute the given values into the rearranged formula: molality (0.175 m) and the mass of water in kilograms (from step 2).
Calculate the moles of KF using the values from step 4. This will give you the number of moles of KF in the solution.
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