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Multiple Choice
An aqueous solution contains 36% HCl by mass. If the density of the solution is 1.18 g/mL, what is the molality of HCl in the solution?
A
15.2 mol/kg
B
12.0 mol/kg
C
9.8 mol/kg
D
7.5 mol/kg
Verified step by step guidance
1
First, understand that molality is defined as the number of moles of solute (HCl in this case) per kilogram of solvent. The formula for molality (m) is: m = \( \frac{\text{moles of solute}}{\text{kilograms of solvent}} \).
Calculate the mass of HCl in a given mass of solution. Assume you have 100 g of solution for simplicity. Since the solution is 36% HCl by mass, the mass of HCl is 36 g.
Determine the moles of HCl using its molar mass. The molar mass of HCl is approximately 36.46 g/mol. Use the formula: \( \text{moles of HCl} = \frac{\text{mass of HCl}}{\text{molar mass of HCl}} \).
Calculate the mass of the solvent (water) in the solution. Since the total mass of the solution is 100 g and the mass of HCl is 36 g, the mass of water is 64 g. Convert this mass to kilograms by dividing by 1000.
Finally, calculate the molality of the solution using the formula: m = \( \frac{\text{moles of HCl}}{\text{kilograms of water}} \). Insert the values obtained from the previous steps to find the molality.