Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

14. Solutions

Molality

General Chemistry

14. Solutions

Molality

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Multiple Choice

A solution is prepared by dissolving 43.0 g potassium chlorate, KClO₃, in enough water to make 100.0 mL of solution. If the density of the solution is 1.760 g/mL, what is the molality of KClO₃ in the solution?

1.99 m

3.51 m

2.64 m

4.70 m

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Verified step by step guidance

Calculate the number of moles of KClO3. First, find the molar mass of KClO3 by adding the atomic masses of potassium (K), chlorine (Cl), and three oxygen (O) atoms. Use the periodic table to find these values.

Convert the mass of KClO3 to moles using the formula: \( \text{moles of KClO3} = \frac{\text{mass of KClO3}}{\text{molar mass of KClO3}} \).

Determine the mass of the solution using its volume and density. Use the formula: \( \text{mass of solution} = \text{density} \times \text{volume} \).

Calculate the mass of the solvent (water) by subtracting the mass of KClO3 from the total mass of the solution.

Find the molality of the solution using the formula: \( \text{molality} = \frac{\text{moles of solute}}{\text{kilograms of solvent}} \). Convert the mass of the solvent from grams to kilograms before using it in the formula.