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Ch. 16 - The Molecular Basis of Inheritance
Campbell - Campbell Biology 11th Edition
Urry11th EditionCampbell BiologyISBN: 9789357423311Not the one you use?Change textbook
Chapter 16, Problem 3

In analyzing the number of different bases in a DNA sample, which result would be consistent with the ­ base-pairing rules?
a. A=G
b. A+G=C+T
c. A+T=G+C
d. A=C

Verified step by step guidance
1
Understand the base-pairing rules in DNA: Adenine (A) pairs with Thymine (T), and Guanine (G) pairs with Cytosine (C). This means the amount of A should equal the amount of T, and the amount of G should equal the amount of C.
Consider the option A=G. This would imply that the amount of Adenine is equal to the amount of Guanine, which contradicts the base-pairing rules since A pairs with T, not G.
Evaluate the option A+G=C+T. This option suggests that the sum of Adenine and Guanine equals the sum of Cytosine and Thymine. This is consistent with the base-pairing rules because A pairs with T and G pairs with C, so the total number of purines (A and G) should equal the total number of pyrimidines (C and T).
Analyze the option A+T=G+C. This implies that the sum of Adenine and Thymine equals the sum of Guanine and Cytosine. While this might seem consistent at first glance, it does not necessarily follow the base-pairing rules directly, as it does not account for the specific pairing of A with T and G with C.
Consider the option A=C. This suggests that the amount of Adenine is equal to the amount of Cytosine, which contradicts the base-pairing rules since A pairs with T, not C.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Base Pairing Rules

Base pairing rules in DNA refer to the specific pairing between nitrogenous bases: adenine (A) pairs with thymine (T), and guanine (G) pairs with cytosine (C). This complementary base pairing is due to hydrogen bonding, where A forms two hydrogen bonds with T, and G forms three hydrogen bonds with C, ensuring the DNA double helix structure is stable and consistent.
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Chargaff's Rules

Chargaff's Rule

Chargaff's Rule states that in a DNA molecule, the amount of adenine (A) is equal to thymine (T), and the amount of guanine (G) is equal to cytosine (C). This rule is derived from the base pairing rules and implies that the total purines (A+G) equal the total pyrimidines (C+T), maintaining a consistent ratio across different organisms.
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Chargaff's Rules

DNA Structure

DNA is structured as a double helix, composed of two strands running in opposite directions. Each strand is made up of a sugar-phosphate backbone and nitrogenous bases. The specific pairing of bases (A with T and G with C) across the two strands allows for the replication and transmission of genetic information, as each strand can serve as a template for creating a new complementary strand.
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Discovering the Structure of DNA
Related Practice
Textbook Question

In his work with pneumonia-causing bacteria and mice, Griffith found that

a. The protein coat from pathogenic cells was able to transform nonpathogenic cells.

b. Heat-killed pathogenic cells caused pneumonia.

c. Some substance from pathogenic cells was transferred to nonpathogenic cells, making them pathogenic.

d. The polysaccharide coat of bacteria caused pneumonia.

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Textbook Question

What is the basis for the difference in how the leading and lagging strands of DNA molecules are synthesized?

a. The origins of replication occur only at the 5′ end.

b. Helicases and single-strand binding proteins work at the 5′ end.

c. DNA polymerase can join new nucleotides only to the 3′ end of a pre-existing strand, and the strands are antiparallel.

d. DNA ligase works only in the 3′→5′ direction.

Textbook Question

The elongation of the leading strand during DNA synthesis

a. Progresses away from the replication fork

b. Occurs in the 3′→5′ direction

c. Produces Okazaki fragments

d. Depends on the action of DNA polymerase

Textbook Question

In a nucleosome, the DNA is wrapped around

a. Histones

b. Ribosomes

c. Polymerase molecules

d. A thymine dimer

Textbook Question

E. coli cells grown on 15N medium are transferred to 14N medium and allowed to grow for two more generations (two rounds of DNA replication). DNA extracted from these cells is centrifuged. What density distribution of DNA would you expect in this experiment?

a. One high-density and one low-density band

b. One intermediate-density band

c. One high-density and one intermediate-density band

d. One low-density and one intermediate-density band