A cell that is placed in salty seawater will ________.
a. Take sodium and chloride ions in by diffusion.
b. Move water out of the cell by active transport.
c. Use facilitated diffusion to break apart the sodium and chloride ions.
d. Lose water to the outside of the cell via osmosis.

Question

A cell that is placed in salty seawater will ________.

a. Take sodium and chloride ions in by diffusion.

b. Move water out of the cell by active transport.

c. Use facilitated diffusion to break apart the sodium and chloride ions.

d. Lose water to the outside of the cell via osmosis.

Accepted Answer

Hi everyone. Here's our next problem, identify the type of solution in which a cell will lose water to the outside its cell via osmosis. So let's focus on that lose water. And let's look over our choices to see if anything can be eliminated or chosen right away. And I noticed that choice D. Is all of the above. We've got a possibility that all are correct. But I see that choice C is isotonic and isotonic means we've got no net loss or gain of water from the cell from or to the cell. So that cannot be our correct answer. Because we're talking about a solution where the cell is going to lose water. So choice C. Cannot be correct and therefore Joyce D. Cannot be correct since we've got at least one incorrect choice. So now we've got to figure out is it hipaa tonic or hyper tonic? And that can be a little bit difficult to remember. Um I know we've got a great content video with little illustration. Ways to help remember that. Um For myself, my own little trick is hip a tonic. I look at that round letter O. And I think of cell getting big and round and fat. So implying that water is coming in by osmosis. And when I think of hyper tonic I look at this little E. It looks kind of like a shriveled up little circle. So I think of the cell losing water and kind of shriveling up water out by osmosis. So that helps me remember whether I've got water coming in or water going out. And so then the last step is just to remember why would water be coming in by osmosis? That would be if my solute concentration is higher inside the cell. So the water is coming in by osmosis to attempt to dilute the solute concentration inside the cell and make it the same as that outside the cell. If water is going out, that means the solute concentration is higher outside the cell. So water is going out by osmosis to try and dilute the solid concentration outside. So our problem is asking what is going to be happened when a cell loses water to the outside. And as we saw losing water we think about shriveled up little E. And we know the answer is choice be hyper tonic. And again, hippo tonic is water coming in? That's not our answer. So solution in which a cell is losing water is a B hyper tonic solution. Thanks for watching. See you in the next

A cell that is placed in salty seawater will ________.
a. Take sodium and chloride ions in by diffusion.
b. Move water out of the cell by active transport.
c. Use facilitated diffusion to break apart the sodium and chloride ions.
d. Lose water to the outside of the cell via osmosis.

Verified video answer for a similar problem:

Key Concepts

Osmosis

Diffusion

Active Transport

A cell that is placed in salty seawater will ________.a. Take sodium and chloride ions in by diffusion.b. Move water out of the cell by active transport.c. Use facilitated diffusion to break apart the sodium and chloride ions.d. Lose water to the outside of the cell via osmosis.

Verified video answer for a similar problem:

Key Concepts

Osmosis

Diffusion

Active Transport

A cell that is placed in salty seawater will ________.
a. Take sodium and chloride ions in by diffusion.
b. Move water out of the cell by active transport.
c. Use facilitated diffusion to break apart the sodium and chloride ions.
d. Lose water to the outside of the cell via osmosis.