Open Question
In the circuit shown in Fig. E26.31 the batteries have negligible internal resistance and the meters are both idealized. With the switch S open, the voltmeter reads 15.0 V. (b) What will the ammeter read when the switch is closed?
27. Resistors & DC Circuits
Solving Resistor Circuits
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If the current in the resistor is , what is ?
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Verified step by step guidance1
First, identify the components in the circuit: a 50 V battery, a 100 Ω resistor, a 300 Ω resistor, a 200 Ω resistor, and an unknown voltage source E. The current through the 100 Ω resistor is given as 0.12 A.
Use Ohm's Law, V = IR, to calculate the voltage drop across the 100 Ω resistor. Substitute I = 0.12 A and R = 100 Ω into the formula: V = 0.12 A × 100 Ω.
Calculate the voltage drop across the 100 Ω resistor. This voltage drop is the potential difference across the resistor due to the current flowing through it.
Next, apply Kirchhoff's Voltage Law (KVL) to the loop containing the 50 V battery, the 100 Ω resistor, and the unknown voltage source E. According to KVL, the sum of the voltage drops around the loop should equal the sum of the voltage rises.
Set up the equation using KVL: 50 V - voltage drop across 100 Ω resistor - E = 0. Solve for E by rearranging the equation to find the value of the unknown voltage source.
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