Open Question
A 5.5-kg object moving in the +𝓍 direction at 6.5 m/s collides head-on with an 8.0-kg object moving in the ―𝓍 direction at 4.0 m/s. Determine the final velocity of each object if: ;
(c) the 5.5-kg object is at rest after the collision;
11. Momentum & Impulse
Completely Inelastic Collisions
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A1500 kgtruck movingslams into a stationary300 kgcar. The two stick together. How fast are they moving immediately after the collision?
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Verified step by step guidance1
Identify the type of collision: This is an inelastic collision because the truck and car stick together after the collision.
Apply the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.
Calculate the initial momentum of the system. The truck is moving, so its momentum is the product of its mass and velocity: \( p_{\text{truck}} = m_{\text{truck}} \times v_{\text{truck}} \). The car is stationary, so its initial momentum is zero.
Set up the equation for conservation of momentum: \( m_{\text{truck}} \times v_{\text{truck}} + m_{\text{car}} \times v_{\text{car}} = (m_{\text{truck}} + m_{\text{car}}) \times v_{\text{final}} \).
Solve for the final velocity \( v_{\text{final}} \) by dividing the total initial momentum by the total mass of the combined system: \( v_{\text{final}} = \frac{m_{\text{truck}} \times v_{\text{truck}}}{m_{\text{truck}} + m_{\text{car}}} \).
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