Open Question
A 5.5-kg object moving in the +𝓍 direction at 6.5 m/s collides head-on with an 8.0-kg object moving in the ―𝓍 direction at 4.0 m/s. Determine the final velocity of each object if:
(a) the objects stick together;
11. Momentum & Impulse
Completely Inelastic Collisions
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A 70-kg hockey player skates on frictionless ice at 5m/s. An opposing player of mass 110kg collides head-on with him at 4m/s. The two players become entangled after the collision and move together. Determine their final velocity.
A
0.5 m/s in the direction of the opposing player
B
0.5 m/s in the direction of the 70 kg player
C
4.39 m/s in the direction of the opposing player
D
4.39 m/s in the direction of the 70 kg player
Verified step by step guidance1
Identify the type of collision: This is an inelastic collision because the two players become entangled and move together after the collision.
Apply the principle of conservation of momentum: The total momentum before the collision is equal to the total momentum after the collision.
Write the equation for the conservation of momentum: \( m_1 \cdot v_1 + m_2 \cdot v_2 = (m_1 + m_2) \cdot v_f \), where \( m_1 = 70 \text{ kg} \), \( v_1 = 5 \text{ m/s} \), \( m_2 = 110 \text{ kg} \), \( v_2 = -4 \text{ m/s} \) (negative because it's in the opposite direction), and \( v_f \) is the final velocity.
Substitute the known values into the equation: \( 70 \cdot 5 + 110 \cdot (-4) = (70 + 110) \cdot v_f \).
Solve for the final velocity \( v_f \) by simplifying the equation and isolating \( v_f \) on one side.
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