A cube has sides of $4.0\mathrm{cm}$. Inside the cube is a $20\mathrm{nC}$ and a $-30\mathrm{nC}$ charge. What is the net flux through the cube?

A uniform electric field points in the positive x direction and has a magnitude of $40\mathrm{N}/\mathrm{C}$. What is the total flux through a rectangle with height $20\mathrm{cm}$ and width $45\mathrm{cm}$? The rectangle lies in the y-z plane.

A uniform electric field points in the positive x direction and has a magnitude of $40\mathrm{N}/\mathrm{C}$. What is the net flux through a cube with sides $4.0\mathrm{cm}$? The cube has one corner on the origin and the positive x, y, and z axes form three of its edges.

A $4.0\mathrm{cm}\times 5.0\mathrm{cm}$ rectangle lies in the x-y plane; let the normal vector point in the z direction. What is the flux through the rectangle of a uniform electric field $\stackrel{\rightharpoonup }{E}=(-7.8\times {10}^5\widehat{j}+2.3\times 10^5\widehat{k})N/C$

A hemispherical surface with radius r in a region of uniform electric field E→ has its axis aligned parallel to the direction of the field. Calculate the flux through the surface.

A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60° to a uniform electric field of magnitude 14 N/C. (c) For what angle φ between the normal to the sheet and the electric field is the magnitude of the flux through the sheet (i) largest and (ii) smallest? Explain your answers.

A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60° to a uniform electric field of magnitude 14 N/C. (a) Find the magnitude of the electric flux through the sheet. (b) Does the answer to part (a) depend on the shape of the sheet? Why or why not?