Alleles of the IGF-1 gene in dogs, encoding insulin-like growth factor, largely determine whether a domestic dog will be large or small. Dogs with an ancestral dominant allele are large, whereas dogs homozygous for the mutant recessive allele are small. Chondrodysplasia, a short-legged phenotype (as in dachshunds and basset hounds), is caused by a dominant gain-of-function allele of the FGF4 gene. The MSTN gene encodes myostatin, a regulator of muscle development. Dogs with a dominant ancestral allele of the MTSN gene have normal muscle development, while dogs homozygous for recessive mutants in the MTSN gene are 'double muscled' and have trouble running quickly. However, dogs heterozygous for the mutant allele run faster than either of the homozygotes.
You breed a pure-breeding small basset hound of normal musculature with a pure-breeding 'bully' whippet, a double-muscled large dog with normal legs.
What are the genotypes and phenotypes of the F₁ puppies?
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
2. Mendel's Laws of Inheritance
Dihybrid Cross
Struggling with Genetics?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Two organisms with the genotypes Aa bb Cc Dd Ee and Aa Bb Cc dd Ee were crossed. Use the branch method to determine the proportion of the following genotypes in the offspring. II. Aa bb Cc dd ee
A
1/256
B
1/64
C
1/16
D
1/4

1
Identify the genotypes of the parents: Parent 1 is Aa bb Cc Dd Ee and Parent 2 is Aa Bb Cc dd Ee.
Break down the problem by considering each gene separately. For each gene, determine the possible genotypes of the offspring and their probabilities using the branch method.
For the 'A' gene: Both parents are Aa, so the possible offspring genotypes are AA, Aa, and aa. Calculate the probability of each genotype.
For the 'b' gene: Parent 1 is bb and Parent 2 is Bb. The possible offspring genotypes are Bb and bb. Calculate the probability of each genotype.
Repeat the process for the remaining genes ('C', 'D', and 'E') to find the probability of the offspring having the genotype Aa bb Cc dd ee. Multiply the probabilities of each gene to find the overall probability of this specific genotype.
Related Videos
Related Practice
Open Question
3
views