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Ch.13 - Solutions & Their Properties
Chapter 13, Problem 128

When a 2.850 g mixture of the sugars sucrose (C12H22O11) and fructose (C6H12O6) was dissolved in water to a volume of 1.50 L, the resultant solution gave an osmotic pressure of 0.1843 atm at 298.0 K. What is Xsucrose of the mixture?

Verified step by step guidance
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Step 1: Use the formula for osmotic pressure, \( \Pi = iMRT \), where \( \Pi \) is the osmotic pressure, \( i \) is the van't Hoff factor (which is 1 for non-electrolytes like sucrose and fructose), \( M \) is the molarity, \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), and \( T \) is the temperature in Kelvin.
Step 2: Rearrange the formula to solve for molarity \( M \): \( M = \frac{\Pi}{iRT} \). Substitute the given values: \( \Pi = 0.1843 \) atm, \( i = 1 \), \( R = 0.0821 \) L·atm/mol·K, and \( T = 298.0 \) K.
Step 3: Calculate the total moles of solute in the solution using the molarity \( M \) and the volume of the solution (1.50 L): \( \text{moles of solute} = M \times 1.50 \) L.
Step 4: Let \( x \) be the moles of sucrose and \( y \) be the moles of fructose. The total moles of solute is \( x + y \). Use the molar masses of sucrose (342.30 g/mol) and fructose (180.16 g/mol) to set up the equation: \( 342.30x + 180.16y = 2.850 \) g.
Step 5: Solve the system of equations: \( x + y = \text{total moles of solute} \) and \( 342.30x + 180.16y = 2.850 \) g, to find the mole fraction of sucrose, \( X_{\text{sucrose}} = \frac{x}{x+y} \).

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Osmotic Pressure

Osmotic pressure is the pressure required to prevent the flow of solvent into a solution through a semipermeable membrane. It is directly proportional to the concentration of solute particles in the solution, as described by the van 't Hoff equation: π = iCRT, where π is osmotic pressure, i is the van 't Hoff factor, C is molarity, R is the ideal gas constant, and T is temperature in Kelvin.
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Molar Mass and Moles

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). To find the number of moles of a substance in a mixture, the mass of the substance is divided by its molar mass. This concept is essential for calculating concentrations and relating mass to osmotic pressure in solutions.
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Mass Fraction

Mass fraction is a way of expressing the concentration of a component in a mixture, defined as the mass of the component divided by the total mass of the mixture. In this problem, determining the mass fraction of sucrose (Xsucrose) involves calculating the proportion of sucrose's mass relative to the total mass of the sugar mixture, which is crucial for solving for its contribution to the osmotic pressure.
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