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Ch.8 - Basic Concepts of Chemical Bonding
Chapter 8, Problem 104

Potassium peroxide is composed of 70.96% K and 29.04% O. Each peroxide ion has a net charge of 2-. (a) Given the molecular weight of the compound is 110.19, determine the chemical formula of potassium peroxide.

Verified step by step guidance
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Step 1: Determine the molar mass of potassium (K) and oxygen (O) using the periodic table. Potassium has a molar mass of approximately 39.10 g/mol, and oxygen has a molar mass of approximately 16.00 g/mol.
Step 2: Assume you have 100 g of potassium peroxide. This means you have 70.96 g of K and 29.04 g of O. Convert these masses to moles by dividing by their respective molar masses: moles of K = 70.96 g / 39.10 g/mol and moles of O = 29.04 g / 16.00 g/mol.
Step 3: Calculate the mole ratio of K to O by dividing the moles of each element by the smallest number of moles calculated in Step 2. This will help determine the simplest whole number ratio of K to O in the compound.
Step 4: Use the information that each peroxide ion (O2^2-) has a net charge of 2- to deduce the number of oxygen atoms in the peroxide ion. This suggests that the peroxide ion consists of two oxygen atoms.
Step 5: Combine the information from the mole ratio and the charge of the peroxide ion to determine the empirical formula of potassium peroxide. Ensure the total molar mass of the empirical formula matches the given molecular weight of 110.19 g/mol.

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Empirical Formula

The empirical formula represents the simplest whole-number ratio of elements in a compound. In the case of potassium peroxide, the percentages of potassium and oxygen can be converted into moles to find the ratio of K to O, which is essential for determining the empirical formula before deriving the molecular formula.
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Empirical vs Molecular Formula

Molecular Weight

Molecular weight is the sum of the atomic weights of all atoms in a molecule, expressed in grams per mole. For potassium peroxide, knowing the molecular weight (110.19 g/mol) allows us to confirm the correct chemical formula by comparing it to the calculated weight based on the empirical formula.
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Weight Conversion Example

Ionic Charge and Structure

Understanding ionic charges is crucial for determining the correct formula of ionic compounds. In potassium peroxide, the peroxide ion (O2^2-) has a net charge of 2-, which influences how potassium ions (K+) combine with peroxide to form the neutral compound, guiding the final chemical formula.
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Formal Charge
Related Practice
Textbook Question

One scale for electronegativity is based on the concept that the electronegativity of any atom is proportional to the ionization energy of the atom minus its electron affinity: electronegativity = k1I - EA2, where k is a proportionality constant. (c) By using data in Chapter 7, determine the value of k that would lead to an electronegativity of 4.0 for F under this definition.

Textbook Question

One scale for electronegativity is based on the concept that the electronegativity of any atom is proportional to the ionization energy of the atom minus its electron affinity: electronegativity = k1I - EA2, where k is a proportionality constant. (d) Use your result from part (c) to determine the electronegativities of Cl and O using this scale. Use your result to determine the electronegativity of Cl using this scale.

Textbook Question

Acetylene (C2H2) and nitrogen (N2) both contain a triple bond, but they differ greatly in their chemical properties. (b) By referring to Appendix C, look up the enthalpies of formation of acetylene and nitrogen. Which compound is more stable?

Textbook Question

Acetylene (C2H2) and nitrogen (N2) both contain a triple bond, but they differ greatly in their chemical properties. (c) Write balanced chemical equations for the complete oxidation of N2 to form N2O5(g) and of acetylene to form CO2(g) and H2O(g). Write a balanced chemical equation for the complete oxidation of acetylene to form CO2(g) and H2O(g).

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Textbook Question

Acetylene (C2H2) and nitrogen (N2) both contain a triple bond, but they differ greatly in their chemical properties. (d) Calculate the enthalpy of oxidation per mole for N2 and for C2H2 (the enthalpy of formation of N2O5(g) is 11.30 kJ/mol).