(a) By titration, 15.0 mL of 0.1008 M sodium hydroxide is needed to neutralize a 0.2053-g sample of a weak acid. What is the molar mass of the acid if it is monoprotic?
Ch.4 - Reactions in Aqueous Solution
Chapter 4, Problem 108
A fertilizer railroad car carrying 129,840 L of commercial aqueous ammonia (30% ammonia by mass) tips over and spills. The density of the aqueous ammonia solution is 0.88 g/cm³. What mass of citric acid, C₆H₈O₇ (which contains three acidic protons), is required to neutralize the spill?

1
Convert the volume of the aqueous ammonia solution from liters to cubic centimeters (cm³) using the conversion factor 1 L = 1000 cm³.
Calculate the mass of the aqueous ammonia solution using the formula: mass = volume × density. Use the density provided (0.88 g/cm³) and the volume in cm³.
Determine the mass of ammonia (NH₃) in the solution by using the percentage by mass (30%). Multiply the total mass of the solution by 0.30.
Write the balanced chemical equation for the neutralization reaction between ammonia (NH₃) and citric acid (C₆H₈O₇). Each mole of citric acid can neutralize three moles of ammonia.
Calculate the moles of ammonia using its molar mass (17.03 g/mol), then use the stoichiometry from the balanced equation to find the moles of citric acid needed. Finally, convert the moles of citric acid to mass using its molar mass (192.12 g/mol).
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Stoichiometry
Stoichiometry is the calculation of reactants and products in chemical reactions. It involves using balanced chemical equations to determine the proportions of substances involved. In this case, stoichiometry will help calculate how much citric acid is needed to neutralize the ammonia based on their reaction.
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Acid-Base Neutralization
Acid-base neutralization is a chemical reaction where an acid reacts with a base to produce water and a salt. In this scenario, citric acid (an acid) will react with ammonia (a base) to form ammonium citrate and water. Understanding the nature of this reaction is crucial for determining the amount of citric acid required.
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Concentration and Density Calculations
Concentration refers to the amount of solute in a given volume of solution, while density is the mass per unit volume of a substance. To find the mass of ammonia in the spill, one must use the density of the solution and its volume. This mass will then be used in stoichiometric calculations to find the required mass of citric acid.
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Related Practice
Textbook Question
Textbook Question
(b) An elemental analysis of the acid indicates that it is composed of 5.89% H, 70.6% C, and 23.5% O by mass. What is its molecular formula?
Textbook Question
The discovery of hafnium, element number 72, provideda controversial episode in chemistry. G. Urbain, a Frenchchemist, claimed in 1911 to have isolated an elementnumber 72 from a sample of rare earth (elements 58–71)compounds. However, Niels Bohr believed that hafniumwas more likely to be found along with zirconium thanwith the rare earths. D. Coster and G. von Hevesy, workingin Bohr's laboratory in Copenhagen, showed in 1922 thatelement 72 was present in a sample of Norwegian zircon,an ore of zirconium. (The name hafnium comes from theLatin name for Copenhagen, Hafnia). (c) Solid zirconiumdioxide, ZrO2, reacts with chlorine gas in the presenceof carbon. The products of the reaction are ZrCl4 and twogases, CO2 and CO in the ratio 1:2. Write a balanced chemicalequation for the reaction.
Textbook Question
A sample of 8.69 g of Zn(OH)2 is added to 155.0 mL of 0.750 M H2SO4. (b) Which is the limiting reactant in the reaction?
Textbook Question
A sample of 8.69 g of Zn(OH)2 is added to 155.0 mL of 0.750 M H2SO4. (c) How many moles of Zn(OH)2, H2SO4, ZnSO4 are present after the reaction is complete?
Textbook Question
In 2014, a major chemical leak at a facility in West Virginia released 28,390 L of MCHM (4-methylcyclohexylmethanol, C8H16O) into the Elk River. The density of MCHM is 0.9074 g/mL. (a) Calculate the initial molarity of MCHM in the river, assuming that the first part of the river is 2.00 m deep, 90.0 m wide, and 90.0 m long.