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Ch.13 - Properties of Solutions
Chapter 13, Problem 102

The normal boiling point of ethanol, CH3CH2OH, is 78.4 °C. When 9.15 g of a soluble nonelectrolyte is dissolved in 100.0 g of ethanol at that temperature, the vapor pressure of the solution is 7.40 x 10^2 torr. What is the molar mass of the solute?

Verified step by step guidance
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Step 1: Use Raoult's Law to determine the vapor pressure of pure ethanol. Raoult's Law states that the vapor pressure of the solution (P_solution) is equal to the mole fraction of the solvent (X_solvent) times the vapor pressure of the pure solvent (P_pure). Rearrange the equation to solve for P_pure: P_pure = P_solution / X_solvent.
Step 2: Calculate the mole fraction of ethanol in the solution. The mole fraction (X_solvent) is the ratio of the moles of ethanol to the total moles of the solution. First, calculate the moles of ethanol using its molar mass (46.07 g/mol).
Step 3: Calculate the moles of the solute. Use the given mass of the solute (9.15 g) and its unknown molar mass (M) to express the moles of solute as 9.15 g / M.
Step 4: Set up the equation for the mole fraction of ethanol: X_solvent = moles of ethanol / (moles of ethanol + moles of solute). Substitute the expressions for moles of ethanol and moles of solute into this equation.
Step 5: Solve the equation for the molar mass (M) of the solute. Use the known values for the vapor pressure of the solution and the calculated mole fraction to find the molar mass.

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Raoult's Law

Raoult's Law states that the vapor pressure of a solvent in a solution is directly proportional to the mole fraction of the solvent. This principle is crucial for understanding how the addition of a solute affects the vapor pressure of a solvent, such as ethanol in this case. By applying Raoult's Law, one can calculate the change in vapor pressure and relate it to the concentration of the solute.
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Raoult's Law and Vapor Pressure

Mole Fraction

The mole fraction is a way of expressing the concentration of a component in a mixture, defined as the ratio of the number of moles of that component to the total number of moles of all components. In this problem, calculating the mole fraction of ethanol after dissolving the solute is essential for applying Raoult's Law and determining how the solute affects the vapor pressure.
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Mole Fraction Formula

Molar Mass Calculation

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). To find the molar mass of the solute in this problem, one must use the mass of the solute and the number of moles derived from the changes in vapor pressure and mole fraction. This calculation is fundamental for identifying the properties of the solute in the solution.
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Molar Mass Calculation Example
Related Practice
Textbook Question
A 'canned heat' product used to warm buffet dishes consists of a homogeneous mixture of ethanol 1C2H5OH2 andparaffin, which has an average formula of C24H50. Whatmass of C2H5OH should be added to 620 kg of the paraffinto produce 8 torr of ethanol vapor pressure at 35 °C? Thevapor pressure of pure ethanol at 35 °C is 100 torr.
Textbook Question

Two beakers are placed in a sealed box at 25 °C. One beaker contains 30.0 mL of a 0.050 M aqueous solution of a nonvolatile nonelectrolyte. The other beaker contains 30.0 mL of a 0.035 M aqueous solution of NaCl. The water vapor from the two solutions reaches equilibrium. (a) In which beaker does the solution level rise, and in which one does it fall?

Textbook Question

Two beakers are placed in a sealed box at 25 °C. One beaker contains 30.0 mL of a 0.050 M aqueous solution of a nonvolatile nonelectrolyte. The other beaker contains 30.0 mL of a 0.035 M aqueous solution of NaCl. The water vapor from the two solutions reaches equilibrium. (b) What are the volumes in the two beakers when equilibrium is attained, assuming ideal behavior?

Textbook Question

Carbon disulfide (CS2) boils at 46.30 °C and has a density of 1.261 g/mL. (a) When 0.250 mol of a nondissociating solute is dissolved in 400.0 mL of CS2, the solution boils at 47.46 °C. What is the molal boiling-point-elevation constant for CS2?

Textbook Question

Carbon disulfide (CS2) boils at 46.30 °C and has a density of 1.261 g/mL. (b) When 5.39 g of a nondissociating unknown is dissolved in 50.0 mL of CS2, the solution boils at 47.08 °C. What is the molar mass of the unknown?