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Ch.13 - Properties of Solutions
Chapter 13, Problem 51a

Calculate the number of moles of solute present in each of the following aqueous solutions: (a) 600 mL of 0.250 M SrBr2,

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First, understand that molarity (M) is defined as the number of moles of solute per liter of solution. The formula to calculate moles from molarity is: \( \text{moles} = \text{Molarity} \times \text{Volume in Liters} \).
Convert the volume of the solution from milliliters to liters. Since there are 1000 milliliters in a liter, divide the volume in milliliters by 1000. For 600 mL, the conversion is: \( 600 \text{ mL} \div 1000 = 0.600 \text{ L} \).
Use the molarity of the solution to find the number of moles of solute. The molarity of the SrBr2 solution is given as 0.250 M, which means there are 0.250 moles of SrBr2 per liter of solution.
Substitute the values into the formula: \( \text{moles of SrBr2} = 0.250 \text{ M} \times 0.600 \text{ L} \).
Perform the multiplication to find the number of moles of SrBr2 in the solution. This will give you the moles of solute present in the 600 mL of 0.250 M SrBr2 solution.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity (M)

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L). Understanding molarity is crucial for calculating the amount of solute in a given volume of solution, as it directly relates the volume of the solution to the number of moles present.
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Volume Conversion

In chemistry, it is often necessary to convert between different units of volume. In this case, the volume of the solution is given in milliliters (mL), which must be converted to liters (L) for molarity calculations, since 1 L equals 1000 mL. This conversion is essential to ensure that the units are consistent when applying the molarity formula.
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Calculating Moles from Molarity

To find the number of moles of solute in a solution, the formula used is: moles = molarity × volume (in liters). This relationship allows for the direct calculation of moles when both the molarity and the volume of the solution are known. It is a fundamental concept in stoichiometry and solution chemistry.
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