Compare the enthalpy change upon combustion of a unit volume of liquid methane and liquid methanol. From the standpoint of energy production, which substance has the higher enthalpy of combustion per unit volume, given that methane, when liquefied, has a density of 0.466 g/mL, and the density of methanol at 25 °C is 0.791 g/mL?
Verified step by step guidance
1
Identify the chemical formulas and balanced combustion reactions for both methane (CH₄) and methanol (CH₃OH).
Determine the molar mass of methane and methanol using their chemical formulas: CH₄ and CH₃OH.
Calculate the mass of methane and methanol in a given volume using their respective densities: 0.466 g/mL for methane and 0.791 g/mL for methanol.
Convert the mass of each substance to moles using their molar masses.
Use the standard enthalpy of combustion values for methane and methanol to calculate the enthalpy change per mole, then multiply by the number of moles to find the enthalpy change per unit volume for each substance.
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Enthalpy of Combustion
Enthalpy of combustion is the heat released when one mole of a substance is completely burned in oxygen. It is typically expressed in kilojoules per mole (kJ/mol) and is a crucial measure for evaluating the energy content of fuels. Higher enthalpy values indicate greater energy release, making it essential for comparing the energy production potential of different fuels.
Density is defined as mass per unit volume and is a critical factor in determining how much of a substance can fit into a given volume. In this context, the densities of liquid methane and methanol allow us to calculate their respective masses in a unit volume, which is necessary for comparing their enthalpy of combustion on a volumetric basis. Understanding these relationships helps in assessing which fuel provides more energy per unit volume.
Comparative energy density refers to the amount of energy produced per unit volume of a fuel. This concept is vital when evaluating fuels for practical applications, as it helps determine which fuel is more efficient in terms of space and energy output. By calculating the enthalpy of combustion per unit volume for both methane and methanol, we can identify which substance is more advantageous for energy production.