Multiple Choice
Calculate the volume (mL) of 0.500 M NaOH required to reach the equivalence point in the titration of 25.0 mL of 0.650 M HF. Ka for HF = 3.5 × 10−4.
18. Aqueous Equilibrium
Titrations: Weak Acid-Strong Base
Back18. Aqueous Equilibrium
Titrations: Weak Acid-Strong Base
- Multiple ChoiceFor a titration of a weak acid with a strong base, the pH at the equivalence point ________.
- Multiple Choice20.0 mL of 0.500 M HC2H3O2 is titrated with 0.350 M KOH. Determine the pH after 15.0 mL of the base has been added. Ka for HC2H3O2 = 1.8 × 10−5.
- Multiple Choice20.0 mL of 0.500 M HC2H3O2 is titrated with 0.350 M KOH. Determine the pH after 15.0 mL of the base has been added. Ka for HC2H3O2 = 1.8 × 10−5.
- Multiple ChoiceDetermine the pH when 5.00 mL of excess KOH (beyond the equivalence point) has been added to the titration of 20.0 mL of 0.500 M HC2H3O2 with 0.350 M KOH.
- Multiple ChoiceCalculate the pH at the equivalence point for the titration of 20.0 mL of 0.500 M HC2H3O2 with 0.350 M KOH. Ka for HC2H3O2 = 1.8 × 10−5.
- Multiple Choice
In order to create a buffer 7.510 g of sodium cyanide is mixed with 100.0 mL of 0.250 M hydrocyanic acid, HCN. What is the pH of the buffer solution after the addition of 12.0 mL of 0.300 M NaH? Ka = 4.9 × 10−10.
- Multiple Choice
Consider the titration of 75.0 mL of 0.60 M HNO2 with 0.100 M NaOH at the equivalence point. What would be the pH of the solution at the equivalence point? The Ka of HNO2 is 4.6 × 10−4.
- Multiple Choice
Calculate the pH of the solution resulting from the mixing of 55.0 mL of 0.100 M NaCN and 75.0 mL of 0.100 M HCN with 0.0090 moles of NaOH.
- Open Question
How will you detect the endpoint of the titration of the borate ion with HCl?
- Open Question
Calculate the pH when 50.0 mL of 0.150 M KOH is mixed with 20.0 mL of 0.300 M HBrO (Ka = 2.5 × 10-9)
- Multiple Choice20.0 mL of 0.500 M HC2H3O2 is titrated with 0.350 M KOH. Determine the pH after 15.0 mL of the base has been added. Ka for HC2H3O2 = 1.8 × 10⁻⁵.
- Multiple ChoiceA 10.0 mL sample of 0.200 M hydrocyanic acid (HCN) is titrated with 0.0998 M NaOH. What is the pH at the equivalence point? For hydrocyanic acid, pKₐ = 9.31.
- Multiple ChoiceA 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the pH of the solution after the addition of 100.0 mL of KOH. The Ka of HF is 3.5 × 10^-4.
- Multiple ChoiceA 100.0 mL sample of 0.20 mol L⁻¹ HF is titrated with 0.10 mol L⁻¹ KOH. Determine the pH of the solution after the addition of 200.0 mL of KOH. The Kₐ of HF is 3.5 × 10⁻⁴.