Multiple Choice
A mixture of NaCl and NaBr has a mass of 2.01 g and is found to contain 0.77 g of Na. What is the mass of NaBr in the mixture?
3. Chemical Reactions
Stoichiometry
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According to the following reaction, 2 H2S(g) + SO2(g) → 3 S(s) + 2 H2O(l), how many grams of sulfur are formed when 37.4 g of water are produced?
A
48.0 g
B
24.0 g
C
72.0 g
D
18.0 g
Verified step by step guidance1
Identify the molar mass of water (H2O) by adding the atomic masses of hydrogen and oxygen. The molar mass of H2O is approximately 18.02 g/mol.
Calculate the number of moles of water produced using the given mass (37.4 g) and the molar mass of water. Use the formula: \( \text{moles of H2O} = \frac{\text{mass of H2O}}{\text{molar mass of H2O}} \).
Use the stoichiometry of the balanced chemical equation to find the moles of sulfur (S) produced. According to the equation, 2 moles of H2O correspond to 3 moles of S. Set up a proportion to find the moles of S: \( \frac{3 \text{ moles S}}{2 \text{ moles H2O}} = \frac{x \text{ moles S}}{\text{moles of H2O calculated}} \).
Calculate the mass of sulfur produced using the moles of sulfur and its molar mass. The molar mass of sulfur (S) is approximately 32.07 g/mol. Use the formula: \( \text{mass of S} = \text{moles of S} \times \text{molar mass of S} \).
Compare the calculated mass of sulfur with the given options to determine the correct answer.
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