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Multiple Choice
According to the following reaction, what volume of 0.244 M KCl solution is required to react exactly with 50.0 mL of 0.210 M Pb(NO3)2 solution?2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)
A
43.0 mL
B
86.0 mL
C
50.0 mL
D
21.5 mL
Verified step by step guidance
1
First, identify the balanced chemical equation: 2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq). This tells us that 2 moles of KCl react with 1 mole of Pb(NO3)2.
Calculate the moles of Pb(NO3)2 present in the solution using the formula: \( \text{moles} = \text{concentration} \times \text{volume} \). Convert the volume from mL to L by dividing by 1000.
Using the stoichiometry from the balanced equation, determine the moles of KCl required. Since 2 moles of KCl react with 1 mole of Pb(NO3)2, multiply the moles of Pb(NO3)2 by 2 to find the moles of KCl needed.
Calculate the volume of KCl solution required using the formula: \( \text{volume} = \frac{\text{moles}}{\text{concentration}} \). Use the moles of KCl calculated in the previous step and the given concentration of KCl solution.
Convert the volume from liters to milliliters by multiplying by 1000, and compare the calculated volume to the provided answer choices to determine the correct answer.