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Multiple Choice
In a process where 4.80 kg of boiling water is used to raise the temperature of 25.0 kg of water in a bath to body temperature, how much heat is transferred if the heat lost by the boiling water is equal to the heat gained by the room-temperature water?
A
10.08 kJ
B
4800 kJ
C
2010 kJ
D
0.504 kJ
Verified step by step guidance
1
Identify the principle of conservation of energy, which states that the heat lost by the boiling water is equal to the heat gained by the room-temperature water.
Use the formula for heat transfer: \( q = m \cdot c \cdot \Delta T \), where \( q \) is the heat transferred, \( m \) is the mass, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature.
Determine the specific heat capacity of water, which is typically \( 4.18 \text{ J/g°C} \).
Calculate the change in temperature (\( \Delta T \)) for both the boiling water and the room-temperature water. For boiling water, \( \Delta T \) is the difference between 100°C and the final temperature. For the room-temperature water, \( \Delta T \) is the difference between the final temperature and the initial temperature.
Set up the equation \( m_1 \cdot c \cdot \Delta T_1 = m_2 \cdot c \cdot \Delta T_2 \) and solve for the unknown, ensuring that the units are consistent throughout the calculation.