Provide K expression for the reverse of the following reaction: Fe 2 O 3 (s) + 3 H 2 (g) ⇌ 2 Fe(s) + 3 H 2 O(g)

For the following practice question it says, provide your equilibrium constant expression for the reverse of the following reaction. We know that k normally equals products over reactants, but here they want us to do the reverse. All that means is we're just going to flip it where k now equals reactants over products. Now that's all we mean that's all we mean when we say the reverse of the following reaction. But as always, we have to exclude solids and liquids from our equilibrium expression. So here, this solid is going to be excluded and this solid is going to be excluded. We take a look at our chemical reaction. Reactants would be H2 and it has a coefficient of 3 which becomes its exponent, so this is going to be cubed divided by we have H2O, which also has a coefficient of 3 so that's going to be cubed. So here we're going to say that k equals h2 cubed divided by h2o cubed. This would mean that option would be our correct answer.

Table of contents

Skip topic navigation

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

16. Chemical Equilibrium

Equilibrium Constant K

General Chemistry

16. Chemical Equilibrium

Equilibrium Constant K

Previous problemNext problem

Struggling with General Chemistry?

Join thousands of students who trust us to help them ace their exams!Watch the first video

Multiple Choice

Provide K expression for the reverse of the following reaction:
Fe₂O₃(s) + 3 H₂(g) ⇌ 2 Fe(s) + 3 H₂O(g)

Chemical reaction diagram for Fe2O3 and H2 equilibrium.

Chemical reaction diagram for Fe and H2O equilibrium.

Chemical reaction diagram showing reverse reaction of Fe2O3 and H2.

Chemical reaction diagram illustrating equilibrium constant K expression.

Previous problemNext problem

Verified step by step guidance

Identify the given reaction: Fe2O3(s) + 3 H2(g) ⇌ 2 Fe(s) + 3 H2O(g).

Recognize that the equilibrium constant expression (K) for a reaction is based on the concentrations of the gaseous and aqueous species, excluding solids and liquids.

For the forward reaction, the equilibrium expression K is given by: K = ([H2O]^3) / ([H2]^3).

To find the K expression for the reverse reaction, take the reciprocal of the forward reaction's K expression.

Thus, the K expression for the reverse reaction is: K_reverse = ([H2]^3) / ([H2O]^3).

1:14m

Watch next

Master Equilibrium Constant K with a bite sized video explanation from Jules

Start learning

Equilibrium Constant K practice set

Problem sets built by lead tutors

Expert video explanations

Go to Practice

Download the Mobile app

Privacy

Do not sell my personal information

Accessibility

Patent notice

Sitemap

Struggling with General Chemistry?

Provide K expression for the reverse of the following reaction:Fe2O3(s) + 3 H2(g) ⇌ 2 Fe(s) + 3 H2O(g)

Watch next

Equilibrium Constant K practice set

Provide K expression for the reverse of the following reaction:
Fe₂O₃(s) + 3 H₂(g) ⇌ 2 Fe(s) + 3 H₂O(g)