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Multiple Choice
What is the number of d-orbital electrons in the complex Os(O)(NH3)3?
A
4 d-orbital electrons
B
8 d-orbital electrons
C
10 d-orbital electrons
D
6 d-orbital electrons
Verified step by step guidance
1
Identify the oxidation state of the central metal atom, osmium (Os), in the complex Os(O)(NH3)3. Assume the oxidation state of oxygen (O) is -2 and ammonia (NH3) is a neutral ligand.
Set up the equation for the oxidation state: Let x be the oxidation state of Os. The equation is x + (-2) + 3(0) = 0, where -2 is the oxidation state of O and 0 is the oxidation state of each NH3.
Solve the equation for x to find the oxidation state of Os. This will help determine the number of d-electrons.
Determine the electron configuration of neutral Os, which is [Xe] 4f^14 5d^6 6s^2. Adjust this configuration based on the oxidation state found in the previous step.
Calculate the number of d-orbital electrons by subtracting the electrons lost due to the oxidation state from the original number of d-electrons in neutral Os.