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Multiple Choice
What is the number of d-orbital electrons in the complex [Ni(H2O)6]2+ and the total electron count for the nickel ion in this complex?
A
8 d-orbital electrons, 26 total electrons
B
6 d-orbital electrons, 28 total electrons
C
8 d-orbital electrons, 28 total electrons
D
10 d-orbital electrons, 28 total electrons
Verified step by step guidance
1
Identify the oxidation state of nickel in the complex [Ni(H2O)6]2+. Since the complex has a 2+ charge and water (H2O) is a neutral ligand, the oxidation state of nickel is +2.
Determine the electron configuration of a neutral nickel atom. Nickel (Ni) has an atomic number of 28, so its electron configuration is [Ar] 3d^8 4s^2.
Account for the oxidation state of nickel. Since Ni is in the +2 oxidation state, it loses 2 electrons. These electrons are removed from the 4s orbital first, resulting in the electron configuration [Ar] 3d^8.
Count the number of d-orbital electrons in the Ni^2+ ion. From the electron configuration [Ar] 3d^8, we see that there are 8 electrons in the d-orbitals.
Calculate the total electron count for the nickel ion in the complex. The electron configuration [Ar] 3d^8 indicates that there are 18 electrons from the argon core and 8 d-electrons, totaling 26 electrons for the Ni^2+ ion.