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Multiple Choice
What volume, in mL, of 1.34 M RbOH(aq) is needed to completely neutralize 146 mL of 1.56 M H2SO4(aq)?
A
680 mL
B
340 mL
C
170 mL
D
340 mL
Verified step by step guidance
1
Identify the balanced chemical equation for the neutralization reaction: \( \text{H}_2\text{SO}_4 (aq) + 2 \text{RbOH} (aq) \rightarrow \text{Rb}_2\text{SO}_4 (aq) + 2 \text{H}_2\text{O} (l) \). This shows that 1 mole of \( \text{H}_2\text{SO}_4 \) reacts with 2 moles of \( \text{RbOH} \).
Calculate the moles of \( \text{H}_2\text{SO}_4 \) using its concentration and volume: \( \text{moles of } \text{H}_2\text{SO}_4 = 1.56 \text{ M} \times 0.146 \text{ L} \).
Use the stoichiometry from the balanced equation to find the moles of \( \text{RbOH} \) needed: \( \text{moles of } \text{RbOH} = 2 \times \text{moles of } \text{H}_2\text{SO}_4 \).
Calculate the volume of \( \text{RbOH} \) solution required using its concentration: \( \text{Volume of } \text{RbOH} = \frac{\text{moles of } \text{RbOH}}{1.34 \text{ M}} \).
Convert the volume from liters to milliliters by multiplying by 1000, as the final answer is required in mL.