Table of contents

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1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Naming Ionic Compounds

General Chemistry

3. Chemical Reactions

Naming Ionic Compounds

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Multiple Choice

What is the chemical formula for the compound formed between beryllium and the chromate ion?

BeCrO₄

Be₂(CrO₄)₃

Be(CrO₄)₂

Be₂CrO₄

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Verified step by step guidance

Identify the charges of the ions involved: Beryllium (Be) typically forms a +2 cation, and the chromate ion (CrO₄) has a -2 charge.

Determine the ratio of ions needed to balance the charges: Since both Be and CrO₄ have charges of +2 and -2 respectively, they will combine in a 1:1 ratio to neutralize the charges.

Write the chemical formula by combining the ions in the ratio determined: Since the charges are balanced with one of each ion, the formula is BeCrO₄.

Consider the other options: Be₂(CrO₄)₃ and Be(CrO₄)₂ would imply different charge balances, which are not needed here as the charges are already balanced with BeCrO₄.

Verify the chemical formula: Ensure that the total positive charge from beryllium equals the total negative charge from the chromate ion, confirming that BeCrO₄ is the correct formula.