Arrange NaCl, Cl 2 , CCl 4 , and PCl 5 in order of increasing boiling point.

Hey everyone, we're asked to consider the following solutions. 0.10 morality of sodium chloride. 0.15 morality of fructose and 0.12 morality of calcium chloride were asked to rank the solutions in order of decreasing boiling point. To answer this question, we need to use our boiling point elevation equation, which is going to be I times KB times morality. So our KB is the boiling point elevation constant. While our I times our morality is our osmolarity. As we can see right here, our osmolarity is directly proportional to our boiling point elevation. So this means the higher the osmolarity, the higher the boiling point elevation. So let's go ahead and calculate our osmolarity for each solution. And we can go ahead and answer our question, Starting with 0.010 morality of sodium chloride. We're going to ride out our equation and our sodium chloride is going to dissociate into sodium ions plus chlorine ions. Looking at our Van Hoff constant, which is the number of moles of particles formed in solution per mole of solute. We can see that we have to Now to calculate our osmolarity, we have two times 0.010 Morality which will get us to an osmolarity of 0.020. Next looking at our 0.015 Morality of Fructose And we know that fructose does not ionized in solution. So it's van Hoff constant is going to be one since it does not lionize calculating our osmolarity. Once again, we multiply one times 0.015. This will get us to an osmolarity of 0.015. Lastly calculating are 0.012 morality of calcium chloride. Writing out our equation, we have calcium chloride and this is going to dissociate into calcium ions plus two chlorine ions. This will get us to a van Hoff constant of three, calculating our osmolarity. We multiply three times 0. And this will get us to an osmolarity of 0.036. Now, to rank this in order of the highest boiling point to our lowest boiling point. Our highest one is going to be our 0. morality of calcium chloride. Since we had that value of 0.036 for our osmolarity. Next it will be our 0. Morality of our sodium chloride, followed by our 0.015 morality of fructose. And this is going to be our final answers. So I hope that made sense. And let us know if you have any questions