Multiple Choice
What is the expression for the solubility product constant (Ksp) for the dissolution of Ba3(PO4)2 in water?
18. Aqueous Equilibrium
Solubility Product Constant: Ksp
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NiS has a Ksp of 4.0 x 10^-20. What is the solubility of NiS in mol/L?
A
1.5 x 10^-6 M
B
7.3 x 10^-8 M
C
2.0 x 10^-10 M
D
4.5 x 10^-9 M
Verified step by step guidance1
Start by writing the balanced dissolution equation for NiS: NiS(s) ⇌ Ni²⁺(aq) + S²⁻(aq).
Express the solubility product constant (Ksp) for NiS in terms of the concentrations of the ions: Ksp = [Ni²⁺][S²⁻].
Assume the solubility of NiS is 's' mol/L. Therefore, [Ni²⁺] = s and [S²⁻] = s, since one mole of NiS produces one mole of Ni²⁺ and one mole of S²⁻.
Substitute the concentrations into the Ksp expression: Ksp = s × s = s².
Set the Ksp value equal to the expression and solve for 's': 4.0 × 10⁻²⁰ = s². Take the square root of both sides to find the solubility 's'.
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