Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

18. Aqueous Equilibrium

Solubility Product Constant: Ksp

General Chemistry

18. Aqueous Equilibrium

Solubility Product Constant: Ksp

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Multiple Choice

Given the molar solubility of BaCrO₄ in pure water is 1.08×10⁻⁵ M, what is the solubility product constant (Ksp) for BaCrO₄?

1.08×10⁻¹⁰

1.08×10⁻⁵

1.17×10⁻¹⁰

2.16×10⁻⁵

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Verified step by step guidance

Understand the concept of solubility product constant (Ksp). It is the equilibrium constant for the dissolution of a sparingly soluble ionic compound. For BaCrO₄, the dissolution can be represented as: BaCrO₄(s) ⇌ Ba²⁺(aq) + CrO₄²⁻(aq).

Write the expression for the solubility product constant (Ksp) based on the dissolution equation. The Ksp expression is:

K_{sp} = [Ba²⁺][CrO₄²⁻]

Recognize that the molar solubility of BaCrO₄ in water is given as 1.08×10⁻⁵ M. This means that at equilibrium, the concentration of Ba²⁺ ions and CrO₄²⁻ ions in the solution will both be 1.08×10⁻⁵ M.

Substitute the molar solubility values into the Ksp expression. Since both ions have the same concentration, the expression becomes:

K_{sp} = (1.08×10⁻⁵)(1.08×10⁻⁵)

Calculate the product of the concentrations to find the Ksp value. This involves multiplying the molar solubility of Ba²⁺ and CrO₄²⁻ ions to get the solubility product constant.