Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

24. Transition Metals and Coordination Compounds

Atomic Radius & Density of Transition Metals

General Chemistry

24. Transition Metals and Coordination Compounds

Atomic Radius & Density of Transition Metals

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Multiple Choice

Which first-row transition metal has the highest possible oxidation state of +6?

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Verified step by step guidance

Understand that the oxidation state of an element is the charge it would have if all bonds were ionic. Transition metals can have multiple oxidation states.

Recognize that the highest oxidation state for a transition metal is often related to the number of valence electrons it can lose. For first-row transition metals, this is typically the sum of the electrons in the 3d and 4s orbitals.

List the first-row transition metals and their electron configurations: Sc (3d¹ 4s²), Ti (3d² 4s²), V (3d³ 4s²), Cr (3d⁵ 4s¹), Mn (3d⁵ 4s²).

Calculate the maximum oxidation state by counting the total number of electrons in the 3d and 4s orbitals that can be lost. For example, Cr can lose all 6 electrons (3d⁵ 4s¹) to achieve an oxidation state of +6.

Compare the calculated maximum oxidation states for each metal: Sc (+3), Ti (+4), V (+5), Cr (+6), Mn (+7). Identify that Cr has the highest possible oxidation state of +6 among the given options.