Multiple Choice
What is the molarity of a KCl solution made by diluting 75.0 mL of a 0.200 M solution to a final volume of 100.0 mL?
6. Chemical Quantities & Aqueous Reactions
Dilutions
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
What volume of 6 M sulfuric acid is required to prepare 500 mL of a 0.30 M solution?
A
25 mL
B
75 mL
C
50 mL
D
2.5 mL
Verified step by step guidance1
Start by using the dilution formula, which is \( C_1V_1 = C_2V_2 \), where \( C_1 \) and \( V_1 \) are the concentration and volume of the initial solution, and \( C_2 \) and \( V_2 \) are the concentration and volume of the final solution.
Identify the known values: \( C_1 = 6 \text{ M} \), \( C_2 = 0.30 \text{ M} \), and \( V_2 = 500 \text{ mL} \). You need to find \( V_1 \), the volume of the 6 M sulfuric acid solution required.
Rearrange the dilution formula to solve for \( V_1 \): \( V_1 = \frac{C_2V_2}{C_1} \).
Substitute the known values into the equation: \( V_1 = \frac{0.30 \text{ M} \times 500 \text{ mL}}{6 \text{ M}} \).
Calculate \( V_1 \) to find the volume of the 6 M sulfuric acid solution needed to prepare the desired solution.
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