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Multiple Choice
Determine the Lewis Dot Structure for the following ion:O22–.
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Verified step by step guidance
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Identify the total number of valence electrons for the O2^2- ion. Each oxygen atom has 6 valence electrons, and the 2- charge indicates an additional 2 electrons, giving a total of 14 valence electrons.
Arrange the two oxygen atoms side by side and connect them with a single bond. This single bond accounts for 2 of the 14 valence electrons.
Distribute the remaining 12 valence electrons around the oxygen atoms to satisfy the octet rule. Start by placing 6 electrons (3 pairs) around each oxygen atom.
Check if each oxygen atom has a complete octet. If not, consider forming a double bond by sharing a pair of electrons between the oxygen atoms.
Verify the formal charges on each oxygen atom to ensure the most stable structure. The formal charge should be minimized and ideally be zero for each atom in the ion.