Open Question
For the following electrochemical cell
Cu(s) | Cu2(aq, 0.0155 m) || Ag(aq, 2.50 m) | Ag(s)
20. Electrochemistry
Cell Notation
Struggling with General Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Write the half reactions as well as the overall net ionic equation for the following line notation:
Fe (s) | Fe2+ (aq) || Mg2+ (aq) | Mg (s)
A
Anode: Fe (s) → Fe2+ (aq) + 2e-
Cathode: Mg2+ (aq) + 2e- → Mg (s)
Overall: Fe (s) + Mg2+ (aq) → Fe2+ (aq) + Mg (s)
B
Anode: Fe (s) → Fe2+ (aq) + 2e-
Cathode: Mg2+ (aq) + 2e- → Mg (s)
Overall: Fe2+ (aq) + Mg (s) → Fe (s) + Mg2+ (aq)
C
Anode: Fe (s) → Fe2+ (aq) + 2e-
Cathode: Mg (s) → Mg2+ (aq) + 2e-
Overall: Fe (s) + Mg2+ (aq) → Fe2+ (aq) + Mg (s)
D
Anode: Fe2+ (aq) + 2e- → Fe (s)
Cathode: Mg2+ (aq) + 2e- → Mg (s)
Overall: Fe (s) + Mg2+ (aq) → Fe2+ (aq) + Mg (s)
Verified step by step guidance1
Identify the components of the line notation: Fe (s) | Fe2+ (aq) || Mg2+ (aq) | Mg (s). The single vertical line '|' separates different phases, while the double vertical line '||' represents the salt bridge or membrane separating the two half-cells.
Determine the oxidation and reduction processes. Oxidation occurs at the anode, where Fe (s) is converted to Fe2+ (aq) by losing electrons. Reduction occurs at the cathode, where Mg2+ (aq) gains electrons to form Mg (s).
Write the oxidation half-reaction for the anode: Fe (s) → Fe2+ (aq) + 2e-. This shows the loss of electrons by iron as it is oxidized.
Write the reduction half-reaction for the cathode: Mg2+ (aq) + 2e- → Mg (s). This shows the gain of electrons by magnesium ions as they are reduced.
Combine the two half-reactions to write the overall net ionic equation: Fe (s) + Mg2+ (aq) → Fe2+ (aq) + Mg (s). This represents the complete redox reaction occurring in the electrochemical cell.
Related Videos
Related Practice
